# Let n be the number of times the digit 5 will appear

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The number of times the digit 5 will appear while writing the integers from 1 to 1000. Numbers The number of times the digit 5 will appear while writing the integers from 1 to 1000 is. 269; 271; 300; 302; Answer. First, you need to know how many 5's are there from 1 to 100. 5, 15, 25, ... , 95 = ten 5s at the unit's place. Let m (respectively, n) be the number of 5-digit integers obtained by using the digits 1,2,3,4,5 with repetitions (respectively, without repetitions) such that the sum of any two adjacent digits is odd. Then m/n is equal to (A) 9 (B) 12 (C) 15 (D) 18. As we know, a number is divisible by 4, the last 2 digits must be divisible by 4. So, Number of possible last 2 digits will be {12,16, 24, 32, 36, 52, 56, 64} Number of ways of selecting 1 of these number = 8 C 1 =8 ways. We have already taken the last 2 digits, therefor n = 6 - 2 = 4. So, Number of digits to be filled is 3 = 4 P 3 = 4 × 3 ×. Exercise 5. with 5. In general, if there are n objects available. Bytes & Beyond Special ALT Characters. = 26*26*26*10*10*10*10 = 175760000. The first 31 alt codes ... a–z, and digits 0–9. The above is just a small ... matches minimum and maximum number of times of the preceding character. 80 Answer: There are 26 3 · 366 possible.
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